How do you solve #6p^2-3p=0#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer 256 Jan 21, 2017 #6p^2-3p=0 => p=1/2# Explanation: #6p^2-3p=0# Our original equation #<=># #2p^2-p=0# Divide both sides by 3 #<=># #2p^2=p# Add p to both sides #<=># #2p=1# Divide both sides by p #<=># #p=1/2# Divide both sides by 2 Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 1986 views around the world You can reuse this answer Creative Commons License