# How do you solve 6root4(2a+3)=24?

Dec 7, 2016

a = $\frac{253}{2}$ or 126.5

#### Explanation:

$6 \left(\sqrt[4]{2 a + 3}\right) = 24$ First, divide both sides by 6.
$\sqrt[4]{2 a + 3} = 4$ Next, raise both sides to the 4th power.
$2 a + 3 = 256$ Then, subtract 3 and divide by 2.
$2 a = 253$ and a = $\frac{253}{2}$ or 126.5.

Dec 7, 2016

$a = 126.5$

#### Explanation:

divide by 6:

$\sqrt[4]{2 a + 3} = \frac{24}{6} = 4$

raise 4 powers higher:

$2 a + 3 = {4}^{4} = 256$

subtract 3:

$2 a = 253$

divide by 2:

$a = \frac{253}{2} = 126.5$