How do you solve #6root4(2a+3)=24#?

2 Answers
Dec 7, 2016

Answer:

a = #253/2# or 126.5

Explanation:

#6(root(4)(2a+3))=24# First, divide both sides by 6.
#root(4)(2a+3)=4# Next, raise both sides to the 4th power.
#2a+3=256# Then, subtract 3 and divide by 2.
#2a = 253# and a = #253/2# or 126.5.

Dec 7, 2016

Answer:

#a=126.5#

Explanation:

divide by 6:

#root4(2a+3)=24/6=4#

raise 4 powers higher:

#2a+3=4^4=256#

subtract 3:

#2a=253#

divide by 2:

#a=253/2=126.5#