How do you solve #6sqrt(x+5)=30#?

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Answer 1 · 2016-06-02T21:20:37

#x=20#

In steps, isolate first the group that has #x# in it. Then isolate #x#.

Divide both sides by 6

#sqrt(x+5)=30/6=5#

Square both sides

#x+5=5^2#

subtract 5 from both sides

#x=5^2-5#

#x=25-5 = 20#