How do you solve #6x^2=1296#?

1 Answer
Mar 20, 2018

Answer:

See a solution process below:

Explanation:

First, divide each side of the equation by #color(red)(6)# to isolate the #x# term while keeping the equation balanced:

#(6x^2)/color(red)(6) = 1296/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x^2)/cancel(color(red)(6)) = 216#

#x^2 = 216#

Now, take the square root of each side of the equation to to solve for #x# while keeping the equation balanced. Remember, the square root of a number produces both a positive and negative result:

#sqrt(x^2) = +-sqrt(216)#

#x = +-sqrt(36 * 6)#

#x = +-sqrt(36)sqrt(6)#

#x = +-6sqrt(6)#

The Solution Set is: #x = {-6sqrt(6), 6sqrt(6)}#