How do you solve $6x-2<7$ or $8x-2>=3$ ?

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Answer 1 · 2015-07-10T22:21:47

Solve system:
(1) 6x - 2 < 7
(2) $8x - 1 >= 2$

(1) 6x - 2 < 7 -> 6x < 9 --> x < 3/2

(2) $8x - 2 >+ 3 -> 8x >= 5 -> x >= 5/8$

------------------|0-----------|5/8=========|3/2---------------

Note. The critical point (5/8) is included in the solution set.
Answer by half closed interval: [5/8, 3/2)

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