How do you solve #6x-2<7# or #8x-2>=3#?

1 Answer
Jul 10, 2015

Answer:

Solve system:
(1) 6x - 2 < 7
(2) #8x - 1 >= 2#

Explanation:

(1) 6x - 2 < 7 -> 6x < 9 --> x < 3/2

(2) #8x - 2 >+ 3 -> 8x >= 5 -> x >= 5/8#

------------------|0-----------|5/8=========|3/2---------------

Note. The critical point (5/8) is included in the solution set.
Answer by half closed interval: [5/8, 3/2)