# How do you solve 6x-2<7 or 8x-2>=3?

Jul 10, 2015

Solve system:
(1) 6x - 2 < 7
(2) $8 x - 1 \ge 2$

#### Explanation:

(1) 6x - 2 < 7 -> 6x < 9 --> x < 3/2

(2) $8 x - 2 > + 3 \to 8 x \ge 5 \to x \ge \frac{5}{8}$

------------------|0-----------|5/8=========|3/2---------------

Note. The critical point (5/8) is included in the solution set.
Answer by half closed interval: [5/8, 3/2)