# How do you solve 6x^2+ 7x - 20 = 0 by factoring?

Mar 27, 2015

$6 {x}^{2} + 7 x - 20 = 0$
is a quadratic of the form
$a {x}^{2} + b x + c = 0$
which is solved using the formula
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
I would recommend chanting this formula as many times as necessary to remember it forever; this formula will keep showing up.

For the given equation we have
$x = \frac{- 7 \pm \sqrt{49 + 480}}{12}$

$x = \frac{- 7 \pm 23}{12}$

So (after simplifying) the solutions to the given equations are
$x = \frac{15}{6}$ and $x = \frac{4}{3}$