How do you solve $-6x^2-9x+2=0$ using the quadratic formula?

Question

3232 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-03T14:09:51

x=-1.696484724
or
x=0.1964847243

$x={-(-9)\pmsqrt[9^2-(4xx(-6)xx2)]}/(2xx(-6))$

$x={9\pmsqrt[81+48]}/(-12)$

$x={9\pmsqrt[129]}/(-12)$

$x={9+sqrt[129]}/(-12)$ $=> x=-1.696484724$

or

$x={9-sqrt[129]}/(-12)$ $=> x=0.1964847243$

How do you solve -6x^2-9x+2=0-6x^2-9x+2=0 using the quadratic formula?