How do you solve #6x^2 + x = 5# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Waleed A. Oct 12, 2015 #(x + 1)(6x - 5)# Explanation: #6x^2 + x - 5 =0 # #6x^2 +6x - 5x - 5 = 0 # #6x(x + 1) -5(x + 1) = 0 # #(x + 1)(6x - 5)# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 1365 views around the world You can reuse this answer Creative Commons License