# How do you solve 7-2/3x<x-8?

Dec 4, 2016

$x > 9$

#### Explanation:

Usually the goal of solving any inequality or equality is to isolate a variable.

In this case we add $2 \frac{x}{3}$ to both sides to get:

$7 < \left(\frac{5}{3}\right) x - 8$

Then we add 8 on both sides to get:

$15 < \left(\frac{5}{3}\right) x$

Now we divide by $\frac{5}{3}$ on both sides to express the possible values of $x$ in terms of a constant. We check to see if $\frac{5}{3}$ is greater than $0$. It is, so we can divide it on both sides without having to switch signs.

$x > 9$