How do you solve #7-2/3x<x-8#?

1 Answer
Dec 4, 2016

Answer:

#x>9#

Explanation:

Usually the goal of solving any inequality or equality is to isolate a variable.

In this case we add #2x/3# to both sides to get:

#7<(5/3)x-8#

Then we add 8 on both sides to get:

#15<(5/3)x#

Now we divide by #5/3# on both sides to express the possible values of #x# in terms of a constant. We check to see if #5/3# is greater than #0#. It is, so we can divide it on both sides without having to switch signs.

#x>9#