# How do you solve  7(-3y + 2) = 8(3y - 2) ?

Jul 1, 2016

$7 \left(- 3 y + 2\right) = 8 \left(3 y - 2\right)$

First, distribute the seven and eight.

$- 21 y + 14 = 24 y - 16$

Next, add $21 y$ to both sides.

$14 = 45 y - 16$

And then, add sixteen to both sides to isolate the $y$.

$30 = 45 y$

Divide 30 by 45 to solve for $y$

$y = \frac{30}{45}$

Simplify! - Both are divisible by 5.

$y = \frac{6}{9}$

Both are divisible by 3.

$y = \frac{2}{3}$