How do you solve #7( k + 2) + 5\geq 5#?

1 Answer
Mar 4, 2018

Answer:

#k≥-2#

Explanation:

As with any equation, expanding the brackets is always what we do first.

#7(k+2) +5≥5#

-> #7(k+2)#

#7xxk=7k#

#7xx2=14#

Removing the brackets and replacing it with these values.

#7k+14+5 ≥5#

This can collect like terms of the 14+5, as they are on the same side of the equation and are both a constant.

#7k+19≥5#

As to solve any equation we want to isolate #x# to make it be on its own, therefore we need to #-19# to cancel out the #+19#, remember we do this to both sides.

#7k+19≥5 -> 7k≥-14#

as #5-19=-14# it changes to #7k≥-14#

Now to solve an equation like this, we divide the value by how much of the term we have

#therefore# #k=-14/7=-2#

Remember to always put the sign back in...

#k=-2#

-> #k≥-2#