# How do you solve 7( k + 2) + 5\geq 5?

Mar 4, 2018

k≥-2

#### Explanation:

As with any equation, expanding the brackets is always what we do first.

7(k+2) +5≥5

-> $7 \left(k + 2\right)$

$7 \times k = 7 k$

$7 \times 2 = 14$

Removing the brackets and replacing it with these values.

7k+14+5 ≥5

This can collect like terms of the 14+5, as they are on the same side of the equation and are both a constant.

7k+19≥5

As to solve any equation we want to isolate $x$ to make it be on its own, therefore we need to $- 19$ to cancel out the $+ 19$, remember we do this to both sides.

7k+19≥5 -> 7k≥-14

as $5 - 19 = - 14$ it changes to 7k≥-14

Now to solve an equation like this, we divide the value by how much of the term we have

$\therefore$ $k = - \frac{14}{7} = - 2$

Remember to always put the sign back in...

$k = - 2$

-> k≥-2