How do you solve #7+t<=2(t+3)+2#?

1 Answer
May 4, 2017

Answer:

#t>=-1#

Explanation:

One the whole, treat in the same way you do a normal equation. There are exceptions!

Given: #" "7+t<=2(t+3)+2#

subtract 2 from both sides

#5+t<=2(t+3)#

Multiply out the brackets

#5+t<=2t+6#

Subtract 6 from both sides

#-1+t<=2t#

Subtract #t# from both sides

#-1<=t#

#t>=-1" "larr# Notice that the open bit of #>=# has followed the #t#