# How do you solve 7+t<=2(t+3)+2?

May 4, 2017

$t \ge - 1$

#### Explanation:

One the whole, treat in the same way you do a normal equation. There are exceptions!

Given: $\text{ } 7 + t \le 2 \left(t + 3\right) + 2$

subtract 2 from both sides

$5 + t \le 2 \left(t + 3\right)$

Multiply out the brackets

$5 + t \le 2 t + 6$

Subtract 6 from both sides

$- 1 + t \le 2 t$

Subtract $t$ from both sides

$- 1 \le t$

$t \ge - 1 \text{ } \leftarrow$ Notice that the open bit of $\ge$ has followed the $t$