How do you solve $7 (x + 4) > 0$ $7(x+4)>0$ ?

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Answer 1 · 2017-07-21T02:27:04

See a solution process below:

Step 1) Divide each side of the inequality by $7$ $color(red)(7)$ to eliminate the parenthesis while keeping the inequality balanced:

$\frac{7 (x + 4)}{7} > \frac{0}{7}$ $(7(x + 4))/color(red)(7) > 0/color(red)(7)$

$(color(red)(cancel(color(black)(7)))(x + 4))/cancel(color(red)(7)) > 0$

$x + 4 > 0$

Step 2) Subtract $color(red)(4)$ from each side of the inequality to solve for $x$ while keeping the inequality balanced:

$x + 4 - color(red)(4) > 0 - color(red)(4)$

$x + 0 > -4$

$x > -4$

How do you solve 7(x+4)>07(x+4)>07(x+4)>0?