# How do you solve 7v-(6-2v) =12?

May 10, 2018

$v = \frac{3}{7}$
$7 v - \left(6 - 2 v\right) = 12$
So normally, you work on the equation in the parenthesis first, which you have to do, but as they are different, you can't. when I was in Algebra, I was taught, "To compare or combine, you must be the same kind. " so you can't add or multiply $x$ with $y$. you will see though, that you have $7 v$ minus an equation in parenthesis. That means, you have to individually multiply them, by $7 v$ and $- 1$. Worked out, you get:
$- 42 v + 14 v = 12$. Then, just add them, for $- 28 v$. remember, when subtracting, if the bigger number is negative, the whole answer will be negative. $- 28 v = 12$ It's really hard to understand what $- v = 1$ stands for, plus is would be wrong. So, multiply each side of the equation by $- 1$ for $28 v = 12$. Divide each side by four, for $7 v = 3$, and further divide by seven, for $v = \frac{3}{7}$.