How do you solve #8=10 (sqrt x) + 3#?

1 Answer
Dec 8, 2015

Answer:

In an equation like this, you first put the #x#'s to one side and the numbers to the other.

Explanation:

Subtract 3 from both sides:
#->5=10sqrtx#

Then you divide both sides by 10 to isolate the #sqrtx#
#->1/2=sqrtx->sqrtx=1/2#

As a final step, you can square both sides:
#->(sqrtx)^2=(1/2)^2->x=1/4#