How do you solve 8 − 2x < 4?

Jul 24, 2018

$x > 2$

Explanation:

$8 - 2 x < 4$

Add $\textcolor{b l u e}{2 x}$ to both sides:
$8 - 2 x \quad \textcolor{b l u e}{+ \quad 2 x} < 4 \quad \textcolor{b l u e}{+ \quad 2 x}$

$8 < 4 + 2 x$

Subtract $\textcolor{b l u e}{4}$ from both sides:
$8 \quad \textcolor{b l u e}{- \quad 4} < 4 + 2 x \quad \textcolor{b l u e}{- \quad 4}$

$4 < 2 x$

Divide both sides by $\textcolor{b l u e}{2}$:
$\frac{4}{\textcolor{b l u e}{2}} < \frac{2 x}{\textcolor{b l u e}{2}}$

$2 < x$

Therefore,
$x > 2$

Hope this helps!