How do you solve #8 − 2x < 4#?

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Answer 1 · 2018-07-24T19:13:33

#x > 2#

#8 -2x < 4#

Add #color(blue)(2x)# to both sides:
#8 - 2x quadcolor(blue)(+quad2x) < 4 quadcolor(blue)(+quad2x)#

#8 < 4 + 2x#

Subtract #color(blue)4# from both sides:
#8 quadcolor(blue)(-quad4) < 4 + 2x quadcolor(blue)(-quad4)#

#4 < 2x#

Divide both sides by #color(blue)2#:
#4/color(blue)2 < (2x)/color(blue)2#

#2 < x#

Therefore,
#x > 2#

Hope this helps!