How do you solve 8 = sqrt (y + 2)?

Jan 27, 2016

$y = 62$

Explanation:

$8 = \sqrt{y + 2}$

Square both sides

${8}^{2} = {\left[\sqrt{y + 2}\right]}^{2}$

$64 = y + 2$

$y = 64 - 2 = 62$