# How do you solve 8abs(3-3n)-5=91?

Sep 22, 2016

First, isolate the absolute value.

$8 | 3 - 3 n | - 5 = 91$

$8 | 3 - 3 n | = 96$

$| 3 - 3 n | = 12$

We must now consider the negative case and the positive case.

Case 1: The absolute value is positive

$3 - 3 n = 12$

$- 3 n = 9$

$n = - 3$

Case 2: The absolute value is negative

$- \left(3 - 3 n\right) = 12$

$- 3 + 3 n = 12$

$3 n = 15$

$n = 5$

Hence, the solution set is $\left\{- 3 , 5\right\}$.

Hopefully this helps!