How do you solve 8b^2-12b=0?

Mar 20, 2017

$b = 0 , \text{ or } b = \frac{3}{2}$

Explanation:

Factorise by common factors then consider each product separately.

$8 {b}^{2} - 12 b = 0$

$\implies 4 b \left(2 b - 3\right) = 0$

$\text{either } 4 b = 0 \implies b = 0$

$\text{or } 2 b - 3 = 0 \implies b = \frac{3}{2}$