How do you solve # 8c-(c-5)>c+17#?
1 Answer
Feb 16, 2017
Explanation:
distribute bracket on left side of inequality.
#8c-c+5>c+17#
#rArr7c+5>c+17# collect terms in c on left side and numeric values on right side.
subtract c from both sides.
#7c-c+5>cancel(c)cancel(-c)+17#
#rArr6c+5>17# subtract 5 from both sides.
#6c cancel(+5)cancel(-5)>17-5#
#rArr6c>12# To solve for c, divide both sides by 6
#(cancel(6) c)/cancel(6)>12/6#
#rArrc>2" is the solution"#
