# How do you solve  8c-(c-5)>c+17?

Feb 16, 2017

$c > 2$

#### Explanation:

distribute bracket on left side of inequality.

$8 c - c + 5 > c + 17$

$\Rightarrow 7 c + 5 > c + 17$

collect terms in c on left side and numeric values on right side.

subtract c from both sides.

$7 c - c + 5 > \cancel{c} \cancel{- c} + 17$

$\Rightarrow 6 c + 5 > 17$

subtract 5 from both sides.

$6 c \cancel{+ 5} \cancel{- 5} > 17 - 5$

$\Rightarrow 6 c > 12$

To solve for c, divide both sides by 6

$\frac{\cancel{6} c}{\cancel{6}} > \frac{12}{6}$

$\Rightarrow c > 2 \text{ is the solution}$