How do you solve # 8c-(c-5)>c+17#?

1 Answer
Feb 16, 2017

Answer:

#c>2#

Explanation:

distribute bracket on left side of inequality.

#8c-c+5>c+17#

#rArr7c+5>c+17#

collect terms in c on left side and numeric values on right side.

subtract c from both sides.

#7c-c+5>cancel(c)cancel(-c)+17#

#rArr6c+5>17#

subtract 5 from both sides.

#6c cancel(+5)cancel(-5)>17-5#

#rArr6c>12#

To solve for c, divide both sides by 6

#(cancel(6) c)/cancel(6)>12/6#

#rArrc>2" is the solution"#