Question

How do you solve `8x^2 + 28x + 12 = 0` by factoring?

Answer 1

See explanation

Explanation:

We have that

#8x^2+28x+12=0=>4*(2x^2+7x+3)=0=>2x^2+7x+3=0=> 2x^2+6x+x+3=0=>2x(x+3)+(x+3)=0=>(2x+1)(x+3)=0=> x=-1/2 or x=-3#