How do you solve $9^(2x-1)=27^x$ ?

Question

12284 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-08T08:39:26

$color(blue)(x=2$

$9^(2x-1) = 3^(2.(2x-1)) = 3^(4x-2)$

$27^x = 3^(3x)$

Upon equating:

$3^(4x-2) = 3^(3x)$
Since the base is equal , we can equate the powers:

$4x-2 =3x$
$color(blue)(x=2$

How do you solve 9^(2x-1)=27^x9^(2x-1)=27^x?