# How do you solve a^2 + 2a - 48 = 0?

Feb 26, 2016

This trinomial is factorable, so we can solve by factoring.

#### Explanation:

To factor a trinomial of the form $y = a {x}^{2} + b x + c , a = 1$, we must find two numbers that multiply to c and that add to b.

Two numbers that multiply to -48 and that add to 2 are +8 and -6.

$\left(a + 8\right) \left(a - 6\right) = 0$

$a = - 8 \mathmr{and} 6$

Hopefully this helps.