# How do you solve a/(a+3)+a^2/(a+3)=2?

Jun 4, 2018

$a = - 2 \mathmr{and} a = 3$

#### Explanation:

$\frac{a}{a + 3} + {a}^{2} / \left(a + 3\right)$

$\therefore \frac{a + {a}^{2} = 2 \left(a + 3\right)}{a + 3}$

multiply both sides by $a + 3$

$\therefore a + {a}^{2} = 2 a + 6$

$\therefore {a}^{2} + a - 2 a - 6 = 0$

$\therefore {a}^{2} - a - 6 = 0$

$\therefore = \left(a + 2\right) \left(a - 3\right)$

$\therefore a = - 2 \mathmr{and} a = 3$