# How do you solve a quadratic equation in factored form like this: (x+3)(2x-5)=0?

Remember that if $A \times B = 0$ then either $A = 0$ or $B = 0$
For the given factored example: $\left(x + 2\right) \left(2 x + 5\right) = 0$
{:("either",x+2=0," or ",2x+5=0), (rArr,x=-2,,2x=-5), (,,,x=-2 1/2):}