Question

How do you solve a quadratic equation in factored form like this: (x+3)(2x-5)=0?

Answer 1

Remember that if `AxxB=0` then either `A=0` or `B=0`

Explanation:

For the given factored example: `(x+2)(2x+5)=0`

#{:("either",x+2=0," or ",2x+5=0), (rArr,x=-2,,2x=-5), (,,,x=-2 1/2):}#