# How do you solve a triangle if you are given a=162 b=185 and c=323?

$\cos A = \frac{{b}^{2} + {c}^{2} - {a}^{2}}{2 b c} =$(112,310)/(119,510) = 0.94 ->
$\sin B = \frac{b . \sin A}{a} = \frac{185. \left(0.34\right)}{162}$= 0.39 -> B = 22.85 deg