# How do you solve abs(2z+2)-1>3?

Jun 26, 2018

$z > 1$ or $z < - 3$

#### Explanation:

If $| 2 z + 2 | - 1 > 3$, then

either we have $| 2 z + 2 | = 2 z + 2$, in which case $| 2 z + 2 | - 1 > 3$

becomes $2 z + 2 - 1 > 3$

or $2 z > 2$ i.e. $z > 1$

or $| 2 z + 2 | = - 2 z - 2$ (in case it is negative) and we have

$- 2 z - 2 - 1 > 3$

or $- 2 z > 6$ i.e. $z < - 3$