# How do you solve abs(3 - 3/4x) = 1/4?

1. $\left(3 - \frac{3 x}{4}\right) = \frac{1}{4}$--> 12 - 3x = 1 -> 3x = 11 --> $x = \frac{11}{3}$
2.$- \left(3 - \frac{3 x}{4}\right) = \frac{1}{4}$ -> - 12 + 3x = 1 -> 3x = 13 -> $x = \frac{13}{3}$