How do you solve #abs(x+3)=abs(6x+9)#?

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Answer 1 · 2016-04-17T20:50:49

#-6/5#and #-12/7#

Or the expressions inside the brachets are equal, or they are symmetric:

#|x+3|=|6x+9|#

1) #x+3=6x+9#

#-5x=6#

#x=-6/5

2) #x+3=-(6x+9)#

#x+3=-6x-9)#

#7x=-12#

#x=-12/7#