How do you solve and check for extraneous solutions in #sqrt(5x) = -5#?
With the usual meaning for
The usual definition given is that
This equation asks us, to find a number whose non-negative square root is
(This question is similar to asking us to solve
If the point of the exercise is to investigate extraneous solutions, then:
We might try squaring both sides (to get rid of the square root on the left)
This is one way that extraneous solutions can be introduced in the process of solving an equation.