# How do you solve and check for extraneous solutions in #sqrt(x+7) = x + 1#?

##### 1 Answer

#### Answer:

#### Explanation:

Any solution that you will find must satisfy two conditions

#x+7>=0 implies x>= -7# #x+1>=0 implies x>=-1#

Overall, the solution(s) to this equation must satisfy the condition

Start by squaring both sides of the equation to get rid of the radical term

Rearrange this equation into classic quadratic form

Use the *quadratic formula* to find the two solutions to this equation

Only one of these two solutions, *extraneous solution*.

Therefore, the solution to this equation is

Check to see if this is the case