How do you solve #6=sqrt(b+13)#?

2 Answers
Jul 2, 2018

Answer:

#b=23#

Explanation:

As #6=sqrt(b+13)#

squaring we get

#36=b+13#

or #36-13=b+13-13#

or #23=b#

Jul 2, 2018

Answer:

#b=23#

Explanation:

#color(blue)"square both sides"#

#6^2=(sqrt(b+13))^2#

#36=b+13#

#"subtract 13 from both sides"#

#23=brArrb=23#

#color(blue)"As a check"#

#sqrt(23+13)=sqrt36=6larr" correct"#