How do you solve and graph # 2(q - 3) + 6 ≤ -10#?

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Answer 1 · 2018-07-24T18:43:08

#q < -5#

#2(q-3) + 6 <= -10#

Distribute the left side:
#2q - 6 + 6 <= -10#

Simplify the left side:
#2q <= -10#

Divide both sides by #color(blue)2#:
#(2q)/color(blue)2 <= (-10)/color(blue)2#

#q < -5#

Here's a graph of it on a number line:
enter image source here

The open circle on #-5# means that #-5# is not a solution (but anything less than it is).

Hope this helps!