# How do you solve and graph  2(q - 3) + 6 ≤ -10?

Jul 24, 2018

$q < - 5$

#### Explanation:

$2 \left(q - 3\right) + 6 \le - 10$

Distribute the left side:
$2 q - 6 + 6 \le - 10$

Simplify the left side:
$2 q \le - 10$

Divide both sides by $\textcolor{b l u e}{2}$:
$\frac{2 q}{\textcolor{b l u e}{2}} \le \frac{- 10}{\textcolor{b l u e}{2}}$

$q < - 5$

Here's a graph of it on a number line:

The open circle on $- 5$ means that $- 5$ is not a solution (but anything less than it is).

Hope this helps!