How do you solve and graph 3x + 8 ≥ 4x ?

Jul 24, 2018

$x \le 8$

Explanation:

$3 x + 8 \ge 4 x$

Subtract $\textcolor{b l u e}{3 x}$ from both sides:
$3 x + 8 \quad \textcolor{b l u e}{- \quad 3 x} \ge 4 x \quad \textcolor{b l u e}{- \quad 3 x}$

$8 \ge x$

Therefore,
$x \le 8$

Here's a graph of it on a number line:

(mathwarehouse.com)

The closed circle on $8$ means that $8$ is one of the solutions (and anything less than it).

Hope this helps!