How do you solve and graph #5+1/3n<=6#?

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Answer 1 · 2017-03-11T17:38:32

graph{x<=3 [-10, 10, -5, 5]}

#5+1/3n <= 6#

subtract #5#:

#1/3n <= 1#

multiply by #3#:

#n <= 3#

graph of #n = 3#:

enter image source here

if #x <=3#, then the region of inequality is everything left of the vertical line as well as the vertical line itself.

NB: the weak inequality #(<= or >=)# is graphed with a solid line.