How do you solve and graph the compound inequality $2x+5<=11$ and $4(x-1)+12>=0$ ?

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Answer 1 · 2015-07-14T15:11:29

Solve system of linear equations in one variable:
2x + 5 <= 11
4(x - 1) + 12 >= 0

(1) $2x + 5 <= 11 --> 2x <= 6 --> x <= 3$

(2) $4x - 4 + 12 >= 0 --> 4x >= - 8 --> x >= - 2$

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Answer: closed interval [-2, 3]. The 2 critical points (-2) and (3) are included in the solution set.

How do you solve and graph the compound inequality 2x+5<=112x+5<=11 and 4(x-1)+12>=04(x-1)+12>=0?