How do you solve and write the following in interval notation: #12<7/2a+(-2)#?

Question

1111 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-12T21:01:01

#(4,oo)#

As we have #12<7/2a+(-2)#, this is equivalent to

#12-(-2)<7/2a# or

#14<7/2a# or

#7/2a>14# or

#a>(14×2)/7# or

#a>4# which can be written in interval form as

#(4,oo)#