How do you solve and write the following in interval notation: -16x - 8 ≤ -4(3x +1)?
1 Answer
Jun 15, 2017
Explanation:
"distribute the bracket on the right side"
-16x-8<= -12x-4
"add 16x to both sides"
cancel(-16x)cancel(+16x)-8<= -12x+16x-4
rArr-8<= 4x-4
"add 4 to both sides"
-8+4<= 4xcancel(-4)cancel(+4)
rArr-4<= 4x
"divide both sides by 4"
-4/4<=(cancel(4) x)/cancel(4)
rArr-1<=xrArrx>=-1
"in interval notation " [-1,+oo)