How do you solve and write the following in interval notation: #-16x - 8 ≤ -4(3x +1)#?

1 Answer
Jun 15, 2017

Answer:

#[-1,+oo)#

Explanation:

#"distribute the bracket on the right side"#

#-16x-8<= -12x-4#

#"add 16x to both sides"#

#cancel(-16x)cancel(+16x)-8<= -12x+16x-4#

#rArr-8<= 4x-4#

#"add 4 to both sides"#

#-8+4<= 4xcancel(-4)cancel(+4)#

#rArr-4<= 4x#

#"divide both sides by 4"#

#-4/4<=(cancel(4) x)/cancel(4)#

#rArr-1<=xrArrx>=-1#

#"in interval notation " [-1,+oo)#