How do you solve and write the following in interval notation: -16x - 8 ≤ -4(3x +1)?

1 Answer
Jun 15, 2017

[-1,+oo)

Explanation:

"distribute the bracket on the right side"

-16x-8<= -12x-4

"add 16x to both sides"

cancel(-16x)cancel(+16x)-8<= -12x+16x-4

rArr-8<= 4x-4

"add 4 to both sides"

-8+4<= 4xcancel(-4)cancel(+4)

rArr-4<= 4x

"divide both sides by 4"

-4/4<=(cancel(4) x)/cancel(4)

rArr-1<=xrArrx>=-1

"in interval notation " [-1,+oo)