How do you solve and write the following in interval notation: 3x-1≤ 2?

$x \le 1$. In interval notation the solution is $\left(- \infty , 1\right]$
$3 x - 1 \le 2 \mathmr{and} 3 x \le 3 \mathmr{and} x \le 1$. In interval notation the solution is $\left(- \infty , 1\right]$[Ans]