How do you solve and write the following in interval notation: #-3x > 2# OR #(2x + 2) / 3 > 0#?

1 Answer
Nov 26, 2017

Answer:

Solution: # x < -2/3 or x > -1 # . In interval notation expressed as
#x| (-oo , -2/3) uu (-1, oo)#

Explanation:

#-3x >2 or (2x+2)/3>0 # or

# 3x < -2 or (2x+2)>0 # or

# x < -2/3 or 2x > -2 # or

# x < -2/3 or x > -1 #

Solution: # x < -2/3 or x > -1 # . In interval notation expressed as

#x| ( -oo , -2/3) uu (-1, oo)# [Ans]