# How do you solve and write the following in interval notation: -3x > 2 OR (2x + 2) / 3 > 0?

Nov 26, 2017

Solution: $x < - \frac{2}{3} \mathmr{and} x > - 1$ . In interval notation expressed as
$x | \left(- \infty , - \frac{2}{3}\right) \cup \left(- 1 , \infty\right)$

#### Explanation:

$- 3 x > 2 \mathmr{and} \frac{2 x + 2}{3} > 0$ or

$3 x < - 2 \mathmr{and} \left(2 x + 2\right) > 0$ or

$x < - \frac{2}{3} \mathmr{and} 2 x > - 2$ or

$x < - \frac{2}{3} \mathmr{and} x > - 1$

Solution: $x < - \frac{2}{3} \mathmr{and} x > - 1$ . In interval notation expressed as

$x | \left(- \infty , - \frac{2}{3}\right) \cup \left(- 1 , \infty\right)$ [Ans]