# How do you solve and write the following in interval notation: 4-x< -2?

Apr 11, 2018

Solution: $x > 6 \mathmr{and} \left(6 , \infty\right)$
$4 - x < - 2 \mathmr{and} - x < - 2 - 4 \mathmr{and} - x < - 6$ . Multiplying
by $- 1$ on both sides we get, $x > 6 \mathmr{and} \left(6 , \infty\right)$
Solution: $x > 6 \mathmr{and} \left(6 , \infty\right)$ [Ans]