# How do you solve and write the following in interval notation: 4 <x – 5 ≤ 6?

$9 < x \le 11$ In Interval notation: $\left(9 , 11\right]$
$4 < x - 5 \le 6 \mathmr{and} 4 + 5 < x - 5 + 5 \le 6 + 5 \mathmr{and} 9 < x \le 11 \mathmr{and} x = \left(9 , 11\right]$[Ans]