How do you solve and write the following in interval notation: 4x < 2x + 1 ≤ 3x + 2?

Jul 19, 2016

Half closed interval: [-1, 1/2)

Explanation:

Separate solving into 2 parts:
a. 4x < 2x + 1
2x < 1
$x < \frac{1}{2}$
b. $2 x + 1 \le 3 x + 2$
$2 x - 3 x \le 2 - 1$
$- x \le 1$
$x \ge - 1$
Solution set: Half closed interval: [-1, 1/2)
Graph on the number line:

---------------------- - 1 ========== 0 ==== 1/2 ---------------