How do you solve and write the following in interval notation: #-5<3x + 4#?

1 Answer
Jul 26, 2016

Answer:

#-5 < 3x+4color(white)("XX")rArrcolor(white)("XX")-3 < x#
#color(white)("XXXXX")x in (-3, +oo)#

Explanation:

Given
#color(white)("XXX")-5 < 3x+4#

Since we can subtract the same amount to both sides of an inequality without effecting the validity or orientation of the inequality:
#color(white)("XXX")-9 < 3x

We can also divide both sides of an inequality by any amount greater than zero without effecting the validity or orientation of the inequality:
#color(white)("XXX")-3 < x#

If you prefer you could write this as #x > -3# but it's not really necessary.