How do you solve and write the following in interval notation: #5x-4<9x#?
1 Answer
Apr 1, 2017
Explanation:
Collect terms in x on one side and numeric values on the other.
subtract 5x from both sides.
#cancel(5x)cancel(-5x)-4<9x-5x#
#rArr-4<4x# divide both sides by 4
#(-4)/4<(cancel(4) x)/cancel(4)#
#rArr-1 < xrArrx> -1#
#rArrx in(-1,+oo)larrcolor(red)" in interval notation"#
