# How do you solve and write the following in interval notation: 6[5y-(3y-1)] >= 4(3y-7)?

$6 \left(2 y + 1\right) \ge 4 \left(3 y - 7\right)$
$12 y + 6 \ge 12 y - 28$
$12 y - 12 y \ge - 34$