# How do you solve and write the following in interval notation: #x^2 < 3x + 18#?

##### 2 Answers

#### Answer:

#### Explanation:

Rearrange inequality to have zero on the right side.

#rArrx^2-3x-18<0# Factorise the quadratic on the left side.

#rArr(x-6)(x+3)<0# For the left side to be negative, that is < 0 , then.

#x-6>0color(red)" and " x+3<0#

#color(magenta)" OR"#

#x-6<0color(red)" and " x+3>0#

#rArrx<6color(red)" and " x> -3larrcolor(blue)" solution"#

#rArrx in(-3,6)#

#### Answer:

#### Explanation:

Given

Re-write as:

Note that

The left side is a quadratic dividing the domain of