How do you solve and write the following in interval notation: #x ≥ 3# and #x < 1#?

1 Answer
Sep 22, 2016

Answer:

#(-oo,1)# and #[3,oo)#

Explanation:

In interval notation, a range of following types and these are written in interval notation as mentioned against them

#a < x < b# #color(white)(XXXXXXX)(a,b)#

or #a <= x < b# #color(white)(XXXXXX)[a,b)#

or #a < x <= b# #color(white)(XXXXXX)(a,b]#

or #a <= x <= b# #color(white)(XXXXXX)[a,b]#

Here #a# and #b# are lower and upper limits. Observe that symbols #(# and #)# denote that lower and upper limit are excluded and symbols #[# and #]# denote that lower and upper limit are included.

As we have #x>=3# and #x<1#, this can be represented by

#-oo < x < 1# and #3 <= x < oo# i.e. #(-oo,1)# and #[3,oo)#