How do you solve #arcsin(3x-pi)=1/2#?

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Answer 1 · 2018-06-26T13:34:45

#arcsin(3x-pi)=frac(1)(2)#

Take the #sin# of both sides.

#sin(arcsin(3x-pi))=sin(frac(1)(2))#

Use the rule #sin(arcsin(a))=a# (keep in mind that #arcsin(a)# is only defined if #-1leale1#).

#3x-pi=sin(frac(1)(2))#

Add #pi# to both sides.

#3x=sin(frac(1)(2))+pi#

Divide both sides by #3#.

#x=frac(1)(3)sin(frac(1)(2))+frac(1)(3)pi#