# How do you solve #Ax=B# given #A^-1=((2, -1), (3, -2))# and #B=((2), (3))#?

##### 1 Answer

Apr 30, 2016

I found:

#### Explanation:

As in a normal equation we can multiply both sides for the same amount:

where

multiplying the two matrices on the right we get:

where we get, for the incognitas' vector